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Two cells of e.m.f. 's E_1 and E_2are connected in series in a circuit . Let r_1 and r_2 be the internal resistance of the cells. Find the current through the circuit.

Answer»

SOLUTION :The CELLS are in SERIES. E= `E_1 + E_2`
`r_1 and r_2 ` are the INTERNAL resistancescurrent`i=(E_1 + E_2)/((r_1 + r_2))`


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