Saved Bookmarks
| 1. |
Two cells of e.m.f. 's E_1 and E_2are connected in series in a circuit . Let r_1 and r_2 be the internal resistance of the cells. Find the current through the circuit. |
|
Answer» SOLUTION :The CELLS are in SERIES. E= `E_1 + E_2` `r_1 and r_2 ` are the INTERNAL resistancescurrent`i=(E_1 + E_2)/((r_1 + r_2))` |
|