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Two cells of internal resistance r_1 and r_2 and of same emf are connected in series across a resistor of resistance R. If the terminal potential difference across the call of internal resistance r_1 is zero , then the value of R is |
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Answer» `R=2(r_(1)+r_(2))` TERMINAL p.d across 1 st cell is `V_(1)=E-Ir_(1)` GIVEN : `V_(1)=0` `rArrE-Ir_(1)=0` `E-((2E)/(R+r_(1)+r_(2)))r_(1)=0` `E=(2Er_(1))/(R+r_(1)+r_(2))` `R+r_(1)+r_(2)=2r_(1)` or `R=r_(1)-r_(2)` 
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