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Two cells, of voltage 10 V and 2 V and internal resistances 10Omega and 5Omega respectively, are connected in parallel as shown in Fig. Find the effective voltage and effective resistance of the combination. |
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Answer» Solution : Here `epsi_1 = 10V , epsi_2 = 2V , r_1 = 10 Omega " and " r_2 = 5OMEGA` Since +ve terminal of first cell is connected to - ve terminal of second cell, hence equivalent emf of COMBINATION : `epsi_(eff) = (epsi_1 r_2 - epsi_2 r_1)/(r_1 + r_2) = (10 xx 5 - 2 xx 10)/(10+ 5) = 2V` and EFFECTIVE resistance `r_(cell) = (r_1 r_2)/(r_1 + r_2) = (10 xx 5)/(10 + 5) = 3.33 Omega` |
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