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InterviewSolution
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Two charge 3 xx 10^(-8)C and -2 xx 10^(-8)C are located 15 cm apart. At what point on the line joining the two charges the electric potential zero? Take the potential at infinity to be zero. |
Answer» Solution :Let P be the required point on the x-axis where the potential is zero. We have  `1/(4PI epsi_(0)) [(3 xx 10^(-8))/(x xx 10^(-2)) -(2 xx 10^(-8))/((15-x) xx 10^(-2))]=0` where x is in cm. That is `3/x-(2)/(15-x)=0" which gives x=9cm"` If x lies on the extended line OA, the required condition is `3/x -(2)/(x-15)=0` which gives x=45 cm. The electric potential is zero at 9cm and 45 cm AWAY from the positive charge on the side of the negative charge. |
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