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Two charged particles of charge +2q and +q have masses m and2m respectively. Then are kept in uniform electric field allowed to move for the same time. Find the ratio of their kinetic energies. |
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Answer» `1:8` Let `m_(1)=m, m_(2)=2m` Force on particles, `F_(1)=ma_(1)=2QE` `implies F_(2)=2ma_(2)=qE` `a_(1)=(2qE)/m` and `a_(2)=(qE)/(2m)` FINAL velocities of the particle `v_(1)=u_(1)=a_(1)t` `implies v_(1)=(2qE)/m timpliesv_(2)=(qE)/(2m)t` Let `K=` KINETIC energy `K_(1)=1/2m ((qE)/(2m))^(2)t^(2)implies(K_(1))/(K_(2))=16/1` |
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