1.

Two charged particles of equal charges are placed 1 m apart. The initial acceleration of each of them is ms^(-2) . If their equal mass is 10^(-3) gm, find the charge on each of them.

Answer»

`sqrt(1.1) XX 10^(-8)` C
`1.1 xx 10^(-8)` C
`11 xx 10^(8)` C
`sqrt(2) xx 10^(-8)` C

Solution :Suppose equal charge on each particle is Q. `therefore` Force exerts at 1 m distance is `F = (KQ^(2))/(1)^(2)` but F = ma
`therefore ma= (kQ^(2))/1`
`therefore Q^(2) = (ma)/k = (10^(-6) xx 1)/(9 xx 10^(9)) = 0.11 xx 10^(-15)`
`(therefore m = 10^(-3) g = 10^(-6) kg)`
`therefore Q = sqrt(1.1) xx 10^(-8)` C


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