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Two charged particles traverse identical helical paths in a completely opposite sense in a uniform magnetic field vecB=B_(0)hatk. |
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Answer» They have equal z-components of MOMENTA. `P=(2pimvcostheta)/(Bq)` `thereforeq/m=(2pivcostheta)/(PB)""...(1)` (`theta` is angle of VELOCITY of charge particle with x-axis) If motion is not helical `theta=0`. As path of both the particles is identical and helical but of opposite direction in same magnetic field so by law of conservation of momenta, `(e/m)_(1)+(e/m)_(2)=0` |
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