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Two charges 5 xx 10^(-8) and -3 xx 10^(-8)C are located 16 cm apart. At what points (s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero. |
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Answer» Solution :Let O be a point situated at a distance x CM from +ve charge of `5 xx 10^(-8)`C where the NET electric potential is ZERO. For net potential to be zero `V_1 + V_2 = 0`  Thus,`1/(4piepsi_0)[q_1/x+q_2/((r -x))] = 0 or 1/(4piepsi_0)[(5xx10^(-8))/x-(3XX10^(-8))/((16-x))]=0` `rArrx = 10 cm` Again point lies outside the charges at O., then `or 1/(4piepsi_0) [(5xx 10^(-8))/x-(3xx10^(-8))/((x-16))] = 0` `rArrx = 40 cm` |
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