Saved Bookmarks
| 1. |
Two charges 5 xx 10^(-8)C and -3 xx 10^(-8)C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero ? Take the potential at the infinity to be zero. |
|
Answer» <P> SOLUTION :On the line there are two locations where potential BECOMES ZERO.For `P, (5 xx 10^(-8))/(x)=(3 xx 10^(-8))/((16-x))` `5(16-x) =3x, 80x-5x=3x` `8x=80 therefore x=10cm` For `Q, (5 xx 10^(-8))/((16+y))=(3 xx 10^(-8))/(y)` 5y=38+3y 2y=48 y=24 CM i.e, at (16+24)=40 cm from A. 
|
|