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Two charges are at a distance d apart. If a copper plate of thickness d/2 is placed between them, if effective force will be, |
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Answer» 2F  Colombian FORCE exerted between charges `q_1 and q_2` in the absence of copper plate, `F=1/(4pi e_0 K) (q_1q_2)/r^2` `therefore F=1/(4pi e_0) (q_1q_2)/d^2 (because k=1)` Now ,as SHOWN in the FIGURE, after placing given copper plate, new colombian force between `q_1 and q_2` will be `F.=1/(4pi e_0) (q_1q_2)/((sqrtK_1 r_1+sqrtK_2 r_2+sqrtK_3r_3)^2)` Placing the values `F.=1/(4pi e_0) (q_1q_2)/((d/4+infty+d/4)^2)=1/(4 pi e_0)(q_1q_2)/infty^2=0` Note: HEIGHT of copper plate should be give every large otherwise electric field line emanating from `q_1` may reach `q_2` by passing above or below the copper plate. |
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