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Two charges –q and +q are located at points (0, 0, –a) and (0, 0, a), respectively. (a) What is the electrostatic potential at the points (0, 0, z) and (x, y, 0) ? (b) Obtain the dependence of potential on the distance r of a point from the origin when r//a gt gt 1 . (c) How much work is done in moving a small test charge from thepoint (5,0,0) to (–7,0,0) along the x-axis? Does the answer change if the path of the test charge between the same points is not along the x-axis? |
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Answer» Solution :(a) On the axis of the dipole, potential is `(+- 1//4 pi epsilon_(0)) p//(X^(2)-a^(2))`where p =2qa is the magnitude of the dipole moment, the + sign when the point is closer to q and the – sign when it is closer to –q. Normal to the axis, at points (x, y, 0), potential is zero. (B) The DEPENDENCE on r is `1//r^(2)`type. (c) Zero. No, because work done by ELECTROSTATIC field between two points is independent of the path connecting the two points. |
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