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Two charges4muC and 1 muC are placed at distance of 10 cm. Whereshould a third charge be placed between them so that it does not experience any force . |
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Answer» Solution :`Q_(1)=4muC = 4xx10^(-6)C` `Q_(2) =1muC = 1XX10^(-6)C` `d=10cm` Let the THIRD CHARGE Q be placed at a DISTANCE at a distance of X from `Q_(1)` then x = ? `(Q_(1))/(x^(2)) =(Q_(2))/((10-x)^(2))` `(4xx10^(-6))/(x^(2)) =(1xx10^(-6))/((10-x)^(2)), (2)/(x)=(1)/(10-x)` `x=(20)/(3)cm` from `4muC`. |
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