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Two circles with unequal radii,centred at A and B respectively,touch each other externally at T.If BD is tangent to the first circle at D and TC is transverse common tangent meeting BD at C.Also,AT has the length 3 and BT has length 2. Then the length of CD is equal to |
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Answer» 2 BT=2 , AT=3=AD `therefore` AB=5 , AD=3 `therefore` BD=4 From triangle BTC: `COSTHETA="BT"/"BC"=2/"BC"`….(1) From triangle BAD : `cos theta="BD"/"BA"` `costheta=4/5` ….(2) From (1) and (2) `2/"BC"=4/5 rArr BC=5/2` `therefore` CD=BD-BC `=4-5/2` `=3/2` |
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