InterviewSolution
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InterviewSolution
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Two circular coil 1 and 2 are made from the same wire but the radius of the `1^(st)` coil is twice that of the `2^(nd)` coil. What potential difference in volts should be applied across them so that the magnetic field at their centres is the same-A. 3B. 4C. 6D. 2 |
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Answer» Correct Answer - B Let `R_(1)` and `R_(2)` are the radius of coil 1 & 2.if `B_(1)` and `B_(2)` are magnaetic induction at therir centre,then `B_(1)=(mu_(0)I_(1))/(2r_(1))`, and `B_(2)=(mu_(0)I_(2))/(2r_(1))` Since `B_(1)`=`B_(2)`, and `(R_(1)=2R_(2)` therefore `I_(1)=2I_(2)`Again if `R_(1)=2R_(2)` are resitance of the coil 1 and 2 then `R_(1)=2R_(2)`(as R prop length=2pir) and if `V_(1)and V_(2)`are the potential difference across them respectively,then `(V_(1))/(V_(2))=I_(1R_(1))/(I_(2)R_(2))=((2I_(2))(2R_(2)))/(I_(2)R_(2))=4` |
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