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Two circular coils are made from a uniform wire the ratio of radii of circular coils are 2.3 & no. of turns is 3:4. If they are connected in parallel across a battery. A.: Find ratio of magnetic induction at their centres. B: Find the ratio magnetic momentsof 2 coils |
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Answer» <P> Solution :when connected in parallela) `Bprop1/(r^(2)),(B_(1))/(B_(2))=((r_(2))/(r_(1)))^(2)=(3/2)^(2)=9/4` `b)M=niA_("coil")` but `i=V/R=V/(PL)A_("wire")` `rArrM=(VA_("wire"))/(p(2pir_("coil")))(pir_("coil")^(2)),M=(VA_("wire"))/(pxx2)r_("coil")` `(M_(1))/(M_(2))=(r_(1))/(r_(2))=2/3` |
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