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Two circular rings A and B each of radius a = 30 cm are placed coaxially with their axis horizontal in a uniform electric field E = 10^(5) NC^(-1)directed vertically upward as shown in figure. Distance between centers of the rings A and B (C_A and C_B)is 40 cm. Ring A has positive charge q_A = 10muCand B has a negative charge q_B = -20muC. A particle of mass m and charge q = 10muC is released from rest at the center of ring A. If particle moves along C_AC_B, then Work done by electric field, when particle moves from C_A to C_B is |
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Answer» `-1.2 J` `=3.6J` Since only conservative forces act on the system, potential energy CHANGES to kinetic energy. `3.6=(1)/(2)mv^(2)` or `V^(2)=72` or `v=6sqrt(2)ms^(-1)` |
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