1.

Two circular rings A and B each of radius a = 30 cm are placed coaxially with their axis horizontal in a uniform electric field E = 10^(5) NC^(-1)directed vertically upward as shown in figure. Distance between centers of the rings A and B (C_A and C_B)is 40 cm. Ring A has positive charge q_A = 10muCand B has a negative charge q_B = -20muC. A particle of mass m and charge q = 10muC is released from rest at the center of ring A. If particle moves along C_AC_B, then Speed of particle when it reaches at center of B is

Answer»

`6sqrt2 m//s`
`12sqrt2m//s`
`2sqrt6 m//s`
`4sqrt6m//s`

Solution :`W=q(V_(2)-V_(1))=9xx10^(-2)[((10)/(0.3)-(20)/(05))-((10)/(0.5)-(20)/(0.3))]`
`=3.6J`
SINCE only conservative forces act on the system, potential energy CHANGES to kinetic energy.
`3.6=(1)/(2)mv^(2)` or `v^(2)=72` or `v=6sqrt(2)MS^(-1)`


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