InterviewSolution
Saved Bookmarks
| 1. |
Two closed vessels of equal volume containing air at pressure `P_(1)` and temperature `T_(1)` are connected to each other through a narrow tube. If the temperature in one of the vessels is now maintained at `T_(1)` and that in the other at `T_(2)`, what will be the pressure in the vessels?A. `(T_(1))/(2P_(1)T_(2))`B. `(2P_(1)T_(2))/(T_(1)+T_(2))`C. `(2P_(1)T_(2))/(T_(1)-T_(2))`D. `(2P_(1))/(T_(1)+T_(2))` |
|
Answer» Correct Answer - b (b) Let `T_(1)gtT_(2)`, final pressure will be same, Let x mole transfer from A to B vessel. `:." " P_(A)V=(n-x)RT` and `P_(A)V=(n+x)RT_(2)` `:." " x=(n(T_(1)-T_(2)))/(T_(1)+T_(2)),` `"finally "P_(1)xx2V=2nRT_(1),V=(nRT_(1))/(P_(1))` `:." " P_(A)xx(nRT_(1))/(P_(1))=(n-(n(T_(1)-T_(2)))/((T_(1)+T_(2))))RT_(1)` `P_(A)=(2P_(1)T_(2))/(T_(1)+T_(2))` |
|