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Two coherent sources are 0.15 mm apart and fringes are observed 1m away with monochromatic light of wavelength 6000^(0).Find The fringe width in air. |
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Answer» Solution :Fringe width `beta= (LAMBDA D)/(d)= (6000xx 10^(-10)xx1)/(0.15xx10^(-3))` i.e., `beta= 4 MM`. |
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