1.

Two coherent sources S_(1) and S_(2) are situated as shown in figure. Here S_(1) is fixed but S_(2) is performing SHM with amplitude 2cm. Initially S_(2) is at right extem. At time t=(pi)/(2omega) (where omega= angular frequency of SHM) :

Answer»

Phase difference between waves PRODUCE by `S_(1)` and `S_(2)` at point `P` is `(pi)/2`
INTENSITY at point `P` is `2I_(0)`
Intensity at point `P` is `4I_(0)`
Intensity at point `P` is zero

Solution :`/_\phi=(2PI)/(lamda)/_\X`
`/_\phi=(2pi)/16xx4=(pi)/2`
`I=4I_(0)"COS"^(2)(pi)/4=2I_(0)`


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