Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation I=I_(0) sin omega t, where I_(0)=10 A and omega = 100 pi rad/s. The maximum value of e.m.f. in the second coil is

Two coils have a mutual inductance 0.005 H. The current changes in the

1.	Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation I=I_(0) sin omega t, where I_(0)=10 A and omega = 100 pi rad/s. The maximum value of e.m.f. in the second coil is
Answer» `pi` `5pi` `2PI` `4pi` Solution :As `\|e\|=M(dI)/(DT)=M(d)/(dt)(I_(0)sin OMEGA t)=MI_(0)omega cos omega t` `therefore` Maximum e.m.f. induced, `e_(max)=0.005xx10xx100 pi xx1=5pi`.

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Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation I=I_(0) sin omega t, where I_(0)=10 A and omega = 100 pi rad/s. The maximum value of e.m.f. in the second coil is

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