Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to the equation I = I_(0) sin omegat "where" I_(0) = 10 A and omega = 100pi rad s^(-1). The maximum value of emf induced in the second coil is

Two coils have a mutual inductance 0.005 H. The current changes in the

1.	Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to the equation I = I_(0) sin omegat "where" I_(0) = 10 A and omega = 100pi rad s^(-1). The maximum value of emf induced in the second coil is
Answer» `2PIV` `5pi V` `pi V` `4pi V` Solution :Here `I_(1)=I_(0) SIN OMEGAT, " hence "(d I_(1))/(dt)=I_(0) omega cos omega t` `epsi_(2)=M"" (d I_(1))/(dt) =M I_(0) omega cos omegat` `rArr \|epsi_(2)\|_("MAX")=M I_(0) omega=0.005 xx 10 xx 100pi =5piV`

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Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to the equation I = I_(0) sin omegat "where" I_(0) = 10 A and omega = 100pi rad s^(-1). The maximum value of emf induced in the second coil is

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