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Two coils have the mutual inductance of 0.05 H. The current changes in the first coil as `I=I_(0)sin omegat`, where `I_(0)=1A` and `omega=100pi"rad/s"`. The maximum emf induced in secondary coil isA. `4pi`B. `3pi`C. `2pi`D. `pi` |
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Answer» Correct Answer - D `e=M(di)/(dt)=0.005 xxd/dt(i_(0)sinomegat)` `=0.005i_(0)omegacosomegat= e_(0)cosomegat` `therefore" "e_(max)=0.005xx2xx100pi=pi` |
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