1.

Two coils of self inductance L_(1)and L_(2) are connected byin parlleland the thento cell ofemf epsilon and of resistance R throughta Key . Findthe instantaneous currentthroughtL after thekeyis closed .

Answer»


ANSWER :`I_(1)=(epsiL_(2)0)/(R(L_(1)+L_(2))) I =(epsiL_(2)0)/(R(L_(1)+L_(2)))`


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