InterviewSolution
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InterviewSolution
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Two coins are tossed once. Find the probability of (i) getting 2 heads (ii) getting at least 1 head (iii) getting no head (iv) getting 1 head and 1 tail |
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Answer» Correct Answer - (1) `(3)/(4)` (2) `(1)/(4)` "Let S be the sample space" `"Then S"={"HH,HT,TH,TT"}` `thereforen(S)=4.` (1) Let A be the event where at least one head turns up. `"Then A"={HH,HT,TH}` `thereforen(A)=3.` `Now,P(A)=(n(A))/(n(S))` `thereforeP(A)=(3)/(4).` (2) Let B be the event where no head turns up. `Then B={"TT"}" "thereforen(B)=1.` `thereforeP(B)=(n(B))/(n(S))` `thereforeP(B)=(1)/(4).` |
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