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Two coins are tossed simultaneously. Find the probability of getting exactly one head. |
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Answer» Total numbers of elementary events are 2 + 2 = 4 Let E be the event of getting one head Favorable outcome are: TH , HT Numbers of favorable outcomes are = 2 P (exactly one head) = P (E) = \(\frac{2}4\) = \(\frac{1}2\) |
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