1.

Two coins are tossed simultaneously. Find the probability of getting exactly one head.

Answer»

Total numbers of elementary events are 2 + 2 = 4 

Let E be the event of getting one head 

Favorable outcome are: TH , HT 

Numbers of favorable outcomes are = 2 

P (exactly one head) = P (E) = \(\frac{2}4\) = \(\frac{1}2\)



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