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Two coins are tossed simultaneously. What is the probability of getting at least one head? |
Answer» Total numbers of elementary events are 2+ 2 = 4 Let E be the event of getting at least two heads The favorable outcomes are: HH, HT, TH Total numbers of favorable outcomes are 3 P (ATLEAST one head) = P (E) = \(\frac{3}4\) Note: at least one head means the outcome with one head or more will be considered favorable and the outcome with no head at all will be ruled out. |
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