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Two colis have a mutual inductance 0.005 H. The current changes in the first coil according to the equation where A and The maximum value of the emf induced in the second coil is |
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Answer» `2PI` `epsi= 0.005 (d)/(dt) (I_(m) sin omega t)` `epsi= 0.05I_(m) (d)/(dt) (sin omega t)` `= 0.005 I_(m) cos omega t XX omega` `= 0.005 I_(m) omega cos omega t` `= 0.005 xx 10 xx 100pi cos omega t` `epsi= 5pi cos omega t` ....(1) `epsi= epsi_(m) cos omega t` ....(2) From (1) and (2) `epsi_(m)= 5pi` |
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