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Two condensers `C_(1)` and `C_(2)` in a circuit are jhioned as shown in . The potential fo point `A` is ` V_1` and that of `B` is ` V_2` . The potential of point `D` will be ` A. `(1)/(2)(V_(1)+V_(2))`B. `(C_(2)V_(1)+C_(1)V_(2))/(C_(1)+C_(2))`C. `(C_(1)V_(1)+C_(2)V_(2))/(C_(1)+C_(2))`D. `(C_(2)V_(1)-C_(1)V_(2))/(C_(1)+C_(2))`

Answer» Correct Answer - C


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