1.

Two conducting plates M and N, each having large surface area A (on one side), are placed parallel to each other in figure. The plate M is given charge Q_1 and N, charge Q_2(ltQ_1). Then

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ELECTRIC field at point A is `(Q_1-Q_2)//2Aepsilon_0` TOWARD RIGHT.
electric field at point B is `(Q_1-Q_2)//2Aepsilon_0` toward right.
electric potential of N is GREATER than M.
all of the above

Solution :a.,b.
Electric field LINES will be from `M` to `N`, so potential of `N` will be less than that of `M`.


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