Two conducting rails are connected to a source of e.m.f. and form an incline as shown in the figure. A bar of mass 50 g slides without friction down the incline through a vertical magnetic field B. If the length of the bar is 50 cm and a current of 2.5 A is provided by the battery, for what value of B will the bar slide at a constant velocity ? (g = 10 m//sec^(2))

Two conducting rails are connected to a source of e.m.f. and form an i

1.	Two conducting rails are connected to a source of e.m.f. and form an incline as shown in the figure. A bar of mass 50 g slides without friction down the incline through a vertical magnetic field B. If the length of the bar is 50 cm and a current of 2.5 A is provided by the battery, for what value of B will the bar slide at a constant velocity ? (g = 10 m//sec^(2))
Answer» Solution : Magnetic force acting on rod (a) Due to `B cos theta, F_(1) = B cos theta iL` (b) Due to `B sin theta,F_(2) = B sin theta iL` For equilibrium: `MG sin theta = F_(1) = B cos theta i L` `B = (mg TAN theta)/(i L)` `= (50 xx 10^(-3) xx tan 37^(@))/((2.5)(0.5))`

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