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Two conducting rings of radii r and 2r move in opposite directions with velocities 2v and v respectively on a conducting surface S. There is a uniform magnetic field of magnitude B perpendicular to the plane of the rings. The potential difference between the highest points of the two rings is |
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Answer» Solution :REPLACE the induced emfs in the rings by cells of emfs `e_1 = B 2r (2v) = 4Brv , e_2 = B(4r) = 4Brv` The equivalent CIRCUIT is  Hence the potential difference between the highest POINTS of the two rings is `V_2 - V_1 = e_1 + e_2 = 8Brv` |
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