Two conductors each of length 12 m lie parallel to each other in air. The centre to center distance between two conductors is 15 xx 10^(-2) m and the current in each conductor is 300 amperes. Determine the force in newton tending to pull the conductors together.

Two conductors each of length 12 m lie parallel to each other in air.

1.	Two conductors each of length 12 m lie parallel to each other in air. The centre to center distance between two conductors is 15 xx 10^(-2) m and the current in each conductor is 300 amperes. Determine the force in newton tending to pull the conductors together.
Answer» SOLUTION :Force between two CONDUCTORS is given by `F=(mu_(0))/(2PI)(i_(1)i_(2)L)/r` Given `l=12m,r=15xx10^(-2)m` `i_(1)=i_(2)=300A` `thereforeF=2xx10^(-5)xx(300xx300xx12)/(15xx10^(-2))=1.44N`

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Two conductors each of length 12 m lie parallel to each other in air. The centre to center distance between two conductors is 15 xx 10^(-2) m and the current in each conductor is 300 amperes. Determine the force in newton tending to pull the conductors together.

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