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InterviewSolution
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Two conductors each of length 12 m lie parallel to each other in air. The centre to center distance between the conductor in 15 xx 10^(-2) m and the current in each conductor is 300 amperes. Determine the force in newton tending to pull the conductors together. |
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Answer» Solution :Force between two conductors is given by `F = (mu_0)/(2PI) (i_1 i_2l)/(r)` Given L = 12 m , `r = 15 XX 10^(-2) m`. `i_1 = i_2 = 300 A` `therefore F = 2 xx 10^(-7) xx (300 xx 300 xx 12)/(15 xx 10^(-2)) = 1.44 N`. |
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