Two copper wires with their lengths in the ratio 1 : 2 and resistances in the ratio 1 : 2 are connected (i) in series (ii) in parallel with a battery. What will be the ratio of drift velocities of free electrons in two wires in (i) and (ii) ?

Two copper wires with their lengths in the ratio 1 : 2 and resistances

1.	Two copper wires with their lengths in the ratio 1 : 2 and resistances in the ratio 1 : 2 are connected (i) in series (ii) in parallel with a battery. What will be the ratio of drift velocities of free electrons in two wires in (i) and (ii) ?
Answer» Solution : ` (R_1)/(R_2)= (L I_1)/(A_1)xx (A_2)/(lI_2)rArr (I_1 A_2)/(A_1 I_2) rArr(1)/(2), (I_1)/(I_2) = (1)/(2)therefore (A_2)/(A_1)=1 ` (i)in SERIES n eA, ` (V_d) =neA_2(V_d)_ 2 rArr((V_d)_1)/((V_d)_2) = 1 ` (ii)`i_1 R_1 = i_2 R_2 rArr ((V_d)_1)/((V_d)_2) = (2)/(1) `

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Two copper wires with their lengths in the ratio 1 : 2 and resistances in the ratio 1 : 2 are connected (i) in series (ii) in parallel with a battery. What will be the ratio of drift velocities of free electrons in two wires in (i) and (ii) ?

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