Two crossroads , each of width 4 m , run at right angles through the c

1.	Two crossroads , each of width 4 m , run at right angles through the centre of a rectangular park of length 74 m and breadth 48 m. Find the a. area of crossroads . b. cost of cementing the roads at rs 110 per m².
Answer» ong>Answer: width =4m length of first parallel road 74m *AREA of first road 74×4= 296m²* . length of second road 48m *area of second road =48×4=192m²* . area of the common PART of CROSS road with 4 m width that lies at the *center of the park 4x4 = 16m²* . *area of roads = area of first road +area of second cross road−common area* *=(296+192)−16* *=(296+192)−16=488−16* =472m² . *COST of the construction per sq.m =Rs.110* . total cost =472×110 = ₹51920 Step-by-step explanation: hope it's helpful,,,,, @— OP BOY

Two crossroads , each of width 4 m , run at right angles through the centre of a rectangular park of length 74 m and breadth 48 m. Find the a. area of crossroads . b. cost of cementing the roads at rs 110 per m².

Answer»

ong>Answer:

width =4m

length of first parallel road 74m

AREA of first road 74×4= 296m²

length of second road 48m

area of second road =48×4=192m²

area of the common PART of CROSS road with 4 m width that lies at the

center of the park 4x4 = 16m²

area of roads = area of first road +area of second cross road−common area

=(296+192)−16

=(296+192)−16=488−16

COST of the construction per sq.m =Rs.110

Step-by-step explanation:

hope it's helpful,,,,,

@—