1.

Two cyclists cover the same distance in 15 km/hr and 16 km/hr respectively. Findthe distance travelled by each, if one takes 16 min longer than the other does?​

Answer»

Answer:

7..1km

Step-by-step explanation:

Let's GIVE names to the two cyclists.

Let's call the first cyclists to be 'A' and second to be 'B'.

Cyclists 'A' is traveling at a speed of 16 km/hr.

Now ,assuming that the DISTANCE covered by A and B is X km.

We need to find time , because we don't know that.

But we know the formula of time , that is :

\sf   \boxed{\sf \implies \: time =   \dfrac{distance}{speed} }

→ Assuming distance covered by A and B = x

\sf time \: taken \: by \: A  \: with \: respect \: to \: 1km \:  =  \frac{1km}{15}

\sf \implies \: 4 \: minutes

and

\sf  \: time \: taken \: by \: B \: with \: respect \: to \: 1km =  \frac{1km}{16}

\sf \implies \: 3.75 \: minutes

TOTAL time taken by A and B respectively = 6x and 3.75x

Now,

\sf \: 6x - 3.75x = 2.25x

ACCORDING to the question :

\sf \: 2.25x = 16minutes

\implies \sf \: x =  \frac{16}{2.25}

\sf \implies \: x = 7.1

Total distance covered by A and B = 7.1 km

What you need to know ?

  • Speed = Distance /time



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