Two dice are rolled together. Find the probability of getting such num

1.	Two dice are rolled together. Find the probability of getting such numbers on the two dice whose product is 12.
Answer» Number of all possible outcomes = 36 Let E be the event of getting all those numbers whose product is 12. These number are (2,6),(3,4),(4,3) and (6,2) Therefore, p(getting all those numbers whose product is 12) = P(E) = \(\frac{number\,of\,outcomes\,favorable\,to\,E}{number\,of\,all\,possible\,outcomes}\) = \(\frac{4}{36}\) = \(\frac{1}{9}\) Thus, the probability of getting all those numbers whose product is 12 is \(\frac{1}{9}\).

Two dice are rolled together. Find the probability of getting such numbers on the two dice whose product is 12.

Answer»

Number of all possible outcomes = 36

Let E be the event of getting all those numbers whose product is 12.

These number are (2,6),(3,4),(4,3) and (6,2)

Therefore, p(getting all those numbers whose product is 12) = P(E) = \(\frac{number\,of\,outcomes\,favorable\,to\,E}{number\,of\,all\,possible\,outcomes}\) = \(\frac{4}{36}\) = \(\frac{1}{9}\)

Thus, the probability of getting all those numbers whose product is 12 is \(\frac{1}{9}\).

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Two dice are rolled together. Find the probability of getting such numbers on the two dice whose product is 12.

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