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Two dice are thrown simultaneously. Find the probability ofa) getting sum less than 6.b) getting a doublet like (1, 1) (2, 2), (3, 3). |
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Answer» Answer: a) A = sum LESS than 6 A = (1,1),(1,2),(1,3),(1,4),(2,1),(2,3),(3,1),(3,2),(4,1) N(A) = 9 n(s) = 36 p(A) = n(A) / n(s) = 9/36 = 1/4. B) B = doublet B = (1,1),(2,2),(3,3),(4,4),(5,5),(6,6) n(B) = 6. P(B) = n(B) / n(s) = 6/ 36 = 1/6
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