The probability of getting a multiple of 2 on ONE DIE and a multiple of 3 on the other die = 11/36QuestionTwo dice are thrown simultaneously. The probability of getting a multiple of 2 on one die and a multiple of 3 on the other die, isSOLUTIONSample SPACE For The Event(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)Total Number of Events when a single die is thrown once = 6.∴ Total Number of Events when two dice are thrown = 6² = 36.Here , We have to find the  probability of getting a multiple of 2 on one die and a multiple of 3 on the other die.Let us ASSUME that M is the Event for getting a multiple of 2 on one die and a multiple of 3 on the other. The Favorable Events (M) are :-(2, 3), (2, 6), (4,3), (4, 6), (6, 3), (6, 6), (3, 2), (3, 4), (3, 6), (6, 2), (6, 4)The Number of favorable Events = 11.Here, Total Number of Events = 36 The Number of favorable Events = 11