Two dice are thrown simultaneously. The probability of obtaining total

1.	Two dice are thrown simultaneously. The probability of obtaining total score of seven isA. \(\frac{5}{36}\)B. \(\frac{6}{36}\) C. \(\frac{7}{36}\) D. \(\frac{8}{36}\)
Answer» As 2 dice are thrown so there are 6×6 = 36 possibilities. Let E denote the event of getting a total score of 5. E = {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)} ∴ n(E)= 6 Hence, P(E) = \(\frac{6}{36}\) As our answer matches only with option (b) ∴ Option (b) is the only correct choice.

Two dice are thrown simultaneously. The probability of obtaining total score of seven isA. \(\frac{5}{36}\)B. \(\frac{6}{36}\) C. \(\frac{7}{36}\) D. \(\frac{8}{36}\)

Answer»

As 2 dice are thrown so there are 6×6 = 36 possibilities.

Let E denote the event of getting a total score of 5.

E = {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)}

∴ n(E)= 6

Hence,

P(E) = \(\frac{6}{36}\)

As our answer matches only with option (b)

∴ Option (b) is the only correct choice.

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Two dice are thrown simultaneously. The probability of obtaining total score of seven isA. \(\frac{5}{36}\)B. \(\frac{6}{36}\) C. \(\frac{7}{36}\) D. \(\frac{8}{36}\)

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