Two dice are thrown simultaneously. The probability of obtaining a tot

1.	Two dice are thrown simultaneously. The probability of obtaining a total score of 5 isA. \(\frac{1}{18}\)B. \(\frac{1}{12}\) C. \(\frac{1}{9}\)D. none of these
Answer» As 2 dice are thrown so there are 6×6 = 36 possibilities. Let E denote the event of getting a total score of 5. E = {(1,4),(2,3),(3,2),(4,1)} ∴ n(E)=4 Hence, P(E) = \(\frac{4}{36} = \frac{1}{9}\) As our answer matches only with option (c) ∴ Option (c) is the only correct choice.

Two dice are thrown simultaneously. The probability of obtaining a total score of 5 isA. \(\frac{1}{18}\)B. \(\frac{1}{12}\) C. \(\frac{1}{9}\)D. none of these

Answer»

As 2 dice are thrown so there are 6×6 = 36 possibilities.

Let E denote the event of getting a total score of 5.

E = {(1,4),(2,3),(3,2),(4,1)}

∴ n(E)=4

Hence,

P(E) = \(\frac{4}{36} = \frac{1}{9}\)

As our answer matches only with option (c)

∴ Option (c) is the only correct choice.

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Two dice are thrown simultaneously. The probability of obtaining a total score of 5 isA. \(\frac{1}{18}\)B. \(\frac{1}{12}\) C. \(\frac{1}{9}\)D. none of these

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