Two dice are thrown simultaneously. The probability of getting a total

1.	Two dice are thrown simultaneously. The probability of getting a total of 10 is:1. 1/42. 1/63. 1/124. 1/9
Answer» Correct Answer - Option 3 : 1/12 Given: Two dice are thrown simultaneously Formula Used: P(E) = n(E)/n(S) Where, n(E) = Number of favourable events n(S) = Number of possible outcomes Calculation: When two dice throw simultaneously, then total possible outcomes (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2),..............................., (2, 6) ............................................................ ............................................................ (6, 1), (6, 2), ................................(6, 6) Number of possible outcomes n(S) = 6 × 6 ⇒ 36 Number of favourable events n(E) = {(4,6), (6,4), (5,5)} = 3 ⇒ n(E) = 3 Required probability of getting a total of 10 P(E) = 3/36 ⇒ 1/12 ∴ The probability of getting a total of 10 is 1/12.

Two dice are thrown simultaneously. The probability of getting a total of 10 is:1. 1/42. 1/63. 1/124. 1/9

Answer» Correct Answer - Option 3 : 1/12

Given:

Two dice are thrown simultaneously

Formula Used:

P(E) = n(E)/n(S)

Where,

n(E) = Number of favourable events

n(S) = Number of possible outcomes

Calculation:

When two dice throw simultaneously, then total possible outcomes

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2),..............................., (2, 6)

............................................................

(6, 1), (6, 2), ................................(6, 6)

Number of possible outcomes n(S) = 6 × 6

⇒ 36

Number of favourable events n(E) = {(4,6), (6,4), (5,5)} = 3

⇒ n(E) = 3

Required probability of getting a total of 10

P(E) = 3/36

⇒ 1/12

∴ The probability of getting a total of 10 is 1/12.

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