Two dice are thrown simultaneously. What is the probability of getting

1.	Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is at most 5?
Answer» <P> 5/18 In a simultaneous throw of two dice, we have n(s) = 6 x 6 = 36 Let E = event of getting two numbers whose SUM is at most 5. Then E = { (1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1)} therefore, n(E) = 10 And P(E) = p( getting two numbers whose sum is at most 5) P(E) = n(E)/n(s) = 10/36 = 5/18 Hence the ANSWER is 5/18

Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is at most 5?

Answer»

<P> 5/18

In a simultaneous throw of two dice, we have n(s) = 6 x 6 = 36
Let E = event of getting two numbers whose SUM is at most 5.
Then E = { (1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1)}
therefore, n(E) = 10
And P(E) = p( getting two numbers whose sum is at most 5)
P(E) = n(E)/n(s) = 10/36 = 5/18
Hence the ANSWER is 5/18

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Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is at most 5?

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