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Two different isolated coils have self inductances, L_(1)=8 mH and L_(2) = 2mH. The current in one coil is increased at a constant rate. The current in second coil is increased at same constant rate. At a certain instant, the power given to two coils is the same. At that time the current, induced voltage and the energy stored in first coil are i_(1)V_(1) and U_(1) respectively, Corresponding values for second coil at same instant are i_(2), V_(2) and U_(2) respectively. Then, |
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Answer» `(i_(1))/(i_(2)) =(1)/(4)` |
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