InterviewSolution
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InterviewSolution
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Two discs of same moment of inertia rotating their regular axis passing through centre and perpendicular to the plane of disc with angular velocities `omega_(1)` and `omega_(2)`. They are brought into contact face to the face coinciding the axis of rotation. The expression for loss of enregy during this process is :A. `(1)/(2) I (omega_(1)+omega_(2))^(2)`B. `(1)/(4) I (omega_(1)-omega_(2))^(2)`C. ` I (omega_(1)-omega_(2))^(2)`D. `(1)/(8) I (omega_(1)-omega_(2))^(2)` |
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Answer» Correct Answer - B `DeltaKE =(1)/(2) (I_(1)I_(2))/(I_(1)+I_(2))(omega_(1)-omega_(2))^(2)` ` =(1)/(2) (I^(2))/((2I))(omega_(1)-omega_(2))^(2)` ` =(1)/(4) I(omega_(1)-omega_(2))^(2)` |
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