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Two electric bulbs have filaments of lengths `L` and `2L` diameters `2d` and d and emissivities `3e` and 4e If their temperatures are in the ratio 2:3 their powers will be in the ratio of .A. `8:27`B. `4:27`C. `8:3`D. `4:9` |
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Answer» Correct Answer - B `P =e sigma(4piR^(2))T^(4)rArr` `(P_(1))/(P_(2))=(e_(1))/(e_(2))xx(r_(1))/(r_(2))xx(l_(1))/(l_(2))xx((T_(1))/(T_(2)))^(4)` . |
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