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Two electric charges q_(1) = q and q_(2) = -2q are placed at a distance l = 6a apart. Find the locus of points in the plane of the charges where the field potential is zero |
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Answer» SOLUTION :Direct the coordinate axes as shown in FIG. 24.2. Let M be one of the points where the potential is zero: `varphi=varphi_(1)=(q)/(4pi eposi_(0)r_(1))-(2q)/(4pi epsi_(0)r_(2))=0` Hence `r_(2)=2r_(1)` Substituting `r_(1)= sqrt((3a-x)^(2)+y^(2)) and r_(2)= sqrt((3a+x)^(2)+y^(2))`, we OBTAIN after some manipulations `(x-5a)^(2)+y^(2)=16a^(2)` This is the equation of a circle of radius 4a, with centre at (5a, 0) 
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