Saved Bookmarks
| 1. |
Two electrons are held at some separation. A third charge q is to be placed at the midpoint between these two electrons. What should q be so that electric potential energy of the system becomes zero? |
Answer» Solution :The GIVEN arrangement of charges is shown below: Here `q_(e)=` Magnitude of charge on an ELECTRON The potential energy of the system is zero. `therefore U=(1)/(4pi epsilon_(0))[((-q_(e))q)/(r )+(q(-q_(e)))/(r )+((-q_(e))(-q_(e)))/(2R)]=0` `rArr -q q_(e)-q q_(e)+(q_(e)^(2))/(2)=0` `rArr -2q q_(e)= -(q_(e)^(2))/(2)` `rArr 4q=q_(e )` `rArr q=q_(e)//4` |
|