1.

Two elelctric bulbsP and Q have theirresistancein the ratio of 1: 2. Theyare connected in series acrossa battery. Findthe ratio of the power dissipation inthesebulbs.

Answer»

Solution :FORMULA staling that current are EQUAL RATIO POWERS
Power =FR
( The current in the two bulbs , is the same as they are connected in SERIES.
`( P_1)/( P_2)=( I^(2) R_1) /( I^(2) R_2) =(R_1)/(R_2) `
` (1)/(2) `


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