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Two elelctric bulbsP and Q have theirresistancein the ratio of 1: 2. Theyare connected in series acrossa battery. Findthe ratio of the power dissipation inthesebulbs. |
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Answer» Solution :FORMULA staling that current are EQUAL RATIO POWERS Power =FR ( The current in the two bulbs , is the same as they are connected in SERIES. `( P_1)/( P_2)=( I^(2) R_1) /( I^(2) R_2) =(R_1)/(R_2) ` ` (1)/(2) ` |
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